(4z+4)(2z^2+3z+1)=

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Solution for (4z+4)(2z^2+3z+1)= equation:


Simplifying
(4z + 4)(2z2 + 3z + 1) = 0

Reorder the terms:
(4 + 4z)(2z2 + 3z + 1) = 0

Reorder the terms:
(4 + 4z)(1 + 3z + 2z2) = 0

Multiply (4 + 4z) * (1 + 3z + 2z2)
(4(1 + 3z + 2z2) + 4z * (1 + 3z + 2z2)) = 0
((1 * 4 + 3z * 4 + 2z2 * 4) + 4z * (1 + 3z + 2z2)) = 0
((4 + 12z + 8z2) + 4z * (1 + 3z + 2z2)) = 0
(4 + 12z + 8z2 + (1 * 4z + 3z * 4z + 2z2 * 4z)) = 0
(4 + 12z + 8z2 + (4z + 12z2 + 8z3)) = 0

Reorder the terms:
(4 + 12z + 4z + 8z2 + 12z2 + 8z3) = 0

Combine like terms: 12z + 4z = 16z
(4 + 16z + 8z2 + 12z2 + 8z3) = 0

Combine like terms: 8z2 + 12z2 = 20z2
(4 + 16z + 20z2 + 8z3) = 0

Solving
4 + 16z + 20z2 + 8z3 = 0

Solving for variable 'z'.

Factor out the Greatest Common Factor (GCF), '4'.
4(1 + 4z + 5z2 + 2z3) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(1 + 4z + 5z2 + 2z3)' equal to zero and attempt to solve: Simplifying 1 + 4z + 5z2 + 2z3 = 0 Solving 1 + 4z + 5z2 + 2z3 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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